1.6 KB | 1641 chars
"""
[5984: The Bovine Fire Drill](https://www.acmicpc.net/problem/5984)
Tier: Bronze 1
Category: implementation, simulation
"""
import sys
from math import sqrt, pi, sin, factorial, ceil, floor
from datetime import datetime, timedelta
from collections import deque, defaultdict, Counter
from itertools import permutations, combinations, product
from bisect import bisect_left, bisect_right
from heapq import heappush, heappop, heapify
from functools import reduce, lru_cache
from operator import itemgetter, attrgetter, mul, add, sub, truediv
from typing import List, Tuple, Dict, Set, Any, Union
SYS_INPUT = True
RECURSION_LIMIT = 10 ** 7
SET_RECURSION = False
BLANK = " "
if SET_RECURSION:
sys.setrecursionlimit(RECURSION_LIMIT)
inp = lambda : sys.stdin.readline().rstrip() if SYS_INPUT else input()
mii = lambda : [*map(int,inp().split())]
mfi = lambda : [*map(float,inp().split())]
ii = lambda : int(inp())
fi = lambda : float(inp())
isplit = lambda : inp().split()
p = print
def gcd(a, b): return gcd(b, a % b) if b > 0 else a
def lcm(a, b): return a * b // gcd(a, b)
def solve():
ans = 0
n = ii()
l = [i + 1 for i in range(n)]
chk = [False] * (n + 1)
num_idx = {i + 1: i for i in range(n)}
turn = 1
while 1:
current_idx = num_idx[turn]
l[current_idx] = 0
if chk[turn]:
return turn
chk[turn] = True
next_idx = (current_idx + turn) % n
if l[next_idx] == 0:
return turn
next_turn = l[next_idx]
l[next_idx] = turn
num_idx[turn] = next_idx
turn = next_turn
if __name__ == "__main__":
tc = 1
for t in range(1, tc+1):
ret = solve()
p(ret)