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29485번: Производство бензина ↗

Solutions

Python 3
1.0 KB | 1042 chars
"""
[29485: Производство бензина](https://www.acmicpc.net/problem/29485)

Tier: Bronze 1 
Category: implementation, math
"""

import sys
from math import sqrt, pi, sin, factorial, ceil, floor
from datetime import datetime, timedelta

SYS_INPUT = True
RECURSION_LIMIT = 10 ** 7
SET_RECURSION = False
BLANK = " "

if SET_RECURSION:
  sys.setrecursionlimit(RECURSION_LIMIT)

inp = lambda : sys.stdin.readline().rstrip() if SYS_INPUT else input()
mii = lambda : [*map(int,inp().split())]
mfi = lambda : [*map(float,inp().split())]
ii = lambda : int(inp())
fi = lambda : float(inp())
isplit = lambda : inp().split()
p = print

def gcd(a, b): return gcd(b, a % b) if b > 0 else a
def lcm(a, b): return a * b // gcd(a, b)

def solve():
  n = ii()

  l = [mii() for _ in range(n)]

  ans = 1e10
  ans_idx = 1

  for i in range(n):
    A, B, C = l[i]

    if C <= B:
      continue

    k = A / (C - B)

    if ans > k:
      ans = k
      ans_idx = i + 1

  p(ans_idx)

if __name__ == "__main__":
  tc = 1
  for t in range(1, tc+1):
    ret = solve()