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28173번: Another Goose Goose Duck Problem ↗

Solutions

Python 3
784 B | 742 chars
import sys
from math import sqrt, pi, sin, factorial, ceil, floor
from datetime import datetime, timedelta
# sys.setrecursionlimit(10**7)

BLANK = " "

# inp = input
inp = lambda : sys.stdin.readline().rstrip()
mii = lambda x = BLANK : [*map(int,inp().split(x))]
mfi = lambda x = BLANK : [*map(float,inp().split(x))]
ii = lambda : int(inp())
fi = lambda : float(inp())
p = print
def gcd(a, b): return gcd(b, a % b) if b > 0 else a
def lcm(a, b): return a * b // gcd(a, b)


def solve():
	left, right, b, k = mii()

	crt = left

	# l ~ r 구간
	# b 마다 등장

	# 한번의 쿨타임 동안 얼마나 놓치는가.?

	last_duck = left // b + int(-1 if left % b == 0 else 0)

	p(k * (last_duck + 1) * b)


if __name__ == "__main__":
	tc = 1
	for t in range(1, tc+1):
		ret = solve()