2.2 KB | 2221 chars
/*
[20157: 화살을 쏘자!](https://www.acmicpc.net/problem/20157)
Tier: Gold 5
Category: data_structures, geometry, hash_set, math
*/
#include <bits/stdc++.h>
using namespace std;
#define for1(s, e) for(int i = s; i < e; i++)
#define for1j(s, e) for(int j = s; j < e; j++)
#define forEach(k) for(auto i : k)
#define forEachj(k) for(auto j : k)
#define sz(vct) vct.size()
#define all(vct) vct.begin(), vct.end()
#define uniq(vct) sort(all(vct));vct.erase(unique(all(vct)), vct.end())
#define fi first
#define se second
#define INF (1ll << 60ll)
typedef unsigned long long ull;
typedef long long ll;
typedef ll llint;
typedef unsigned int uint;
typedef unsigned long long int ull;
typedef ull ullint;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<double, double> pdd;
typedef pair<double, int> pdi;
typedef pair<string, string> pss;
typedef vector<int> iv1;
typedef vector<iv1> iv2;
typedef vector<ll> llv1;
typedef vector<llv1> llv2;
typedef vector<pii> piiv1;
typedef vector<piiv1> piiv2;
typedef vector<pll> pllv1;
typedef vector<pllv1> pllv2;
typedef vector<pdd> pddv1;
typedef vector<pddv1> pddv2;
const double EPS = 1e-8;
const double PI = acos(-1);
template<typename T>
T sq(T x) { return x * x; }
int sign(ll x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(int x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(double x) { return abs(x) < EPS ? 0 : x < 0 ? -1 : 1; }
ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }
void solve() {
ll N;
cin >> N;
pllv1 ar(N);
for1(0, N) {
cin >> ar[i].first >> ar[i].second;
if(ar[i].first == 0) {
ar[i].second = sign(ar[i].second);
} else if(ar[i].second == 0) {
ar[i].first = sign(ar[i].first);
} else {
ll g = gcd(llabs(ar[i].first), llabs(ar[i].second));
ar[i].first /= g;
ar[i].second /= g;
}
}
sort(ar.begin(), ar.end());
ll idx = 0;
ll cnt = 1;
ll ans = 0;
for1(1, N) {
if(ar[i] != ar[idx]) {
ans = max(ans, cnt);
idx = i;
cnt = 1;
} else {
cnt++;
}
}
ans = max(ans, cnt);
cout << ans;
}
int main() {
ios::sync_with_stdio(0);
cin.tie(NULL);cout.tie(NULL);
int tc = 1; // cin >> tc;
while(tc--) solve();
}