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18353번: 병사 배치하기 ↗

Solutions

C++14
1.2 KB | 1261 chars
#include <bits/stdc++.h>

#define for1(s,n) for(int i = s; i < n; i++)
#define for1j(s,n) for(int j = s; j < n; j++)
#define foreach(k) for(auto i : k)
#define foreachj(k) for(auto j : k)
#define pb(a) push_back(a)
#define sz(a) a.size()

using namespace std;
typedef unsigned long long ull;
typedef long long ll;
typedef vector <int> iv1;
typedef vector <vector<int> > iv2;
typedef vector <ll> llv1;
typedef unsigned int uint;
typedef vector <ull> ullv1;
typedef vector <vector <ull> > ullv2;

llv1 lis(llv1 ar) {
	llv1 v, buffer;
	llv1::iterator vv;
	vector<pair<ll, ll> > d;
	v.pb(2000000000ll);

	ll n = sz(ar);

	for1(0, n){
		if (ar[i] > *v.rbegin()) {
			v.pb(ar[i]);
			d.push_back({ v.size() - 1, ar[i] });
		}
		else {
			vv = lower_bound(v.begin(), v.end(), ar[i]);
			*vv = ar[i];
			d.push_back({ vv - v.begin(), ar[i] });
		}
	}

	for(int i = sz(d) - 1; i > -1; i--){
		if(d[i].first == sz(v)-1){
				buffer.pb(d[i].second);
				v.pop_back();
		}
	}

	reverse(buffer.begin(), buffer.end());

	return buffer;
}

int main() {
  ios::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
  
	ll N, a;
	llv1 ar;
	
	cin >> N;
	for1(0, N) {
		cin >> a;
		ar.push_back(a);
	}
	
	reverse(ar.begin(), ar.end());

  llv1 ret = lis(ar);
	
	cout << N - ret.size();
}