2.3 KB | 2169 chars
/*
[1781: 컵라면](https://www.acmicpc.net/problem/1781)
Tier: Gold 2
Category: data_structures, greedy, priority_queue, sorting
*/
#include <bits/stdc++.h>
using namespace std;
#define for1(s, e) for(int i = s; i < e; i++)
#define for1j(s, e) for(int j = s; j < e; j++)
#define forEach(k) for(auto i : k)
#define forEachj(k) for(auto j : k)
#define sz(vct) vct.size()
#define all(vct) vct.begin(), vct.end()
#define sortv(vct) sort(vct.begin(), vct.end())
#define uniq(vct) sort(all(vct));vct.erase(unique(all(vct)), vct.end())
#define fi first
#define se second
#define INF (1ll << 60ll)
typedef unsigned long long ull;
typedef long long ll;
typedef ll llint;
typedef unsigned int uint;
typedef unsigned long long int ull;
typedef ull ullint;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<double, double> pdd;
typedef pair<double, int> pdi;
typedef pair<string, string> pss;
typedef vector<int> iv1;
typedef vector<iv1> iv2;
typedef vector<ll> llv1;
typedef vector<llv1> llv2;
typedef vector<pii> piiv1;
typedef vector<piiv1> piiv2;
typedef vector<pll> pllv1;
typedef vector<pllv1> pllv2;
typedef vector<pdd> pddv1;
typedef vector<pddv1> pddv2;
const double EPS = 1e-8;
const double PI = acos(-1);
template<typename T>
T sq(T x) { return x * x; }
int sign(ll x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(int x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(double x) { return abs(x) < EPS ? 0 : x < 0 ? -1 : 1; }
ll N;
pllv1 ar;
void solve() {
cin >> N;
ar.resize(N);
// 데드라인이 짧은 순서대로 pq에 넣는다.
// 만약 pq 안에 들어있는 것들의 개수보다 데드라인이 작다면, 크기를 비교해서 더 작은 것을 빼고 넣는다.
// pq 안에 들어있는 개수보다 데드라인이 크다면, pq에 넣는다.
priority_queue <ll, llv1, greater<ll>> pq;
for1(0, N) {
cin >> ar[i].fi >> ar[i].se;
}
sort(all(ar), [](pll a, pll b) {
if(a.fi == b.fi) return a.se > b.se;
return a.fi < b.fi;
});
ll ans = 0;
for1(0, N) {
pq.push(ar[i].se);
if(pq.size() > ar[i].fi) pq.pop();
}
while(!pq.empty()) {
ans += pq.top();
pq.pop();
}
cout << ans << '\n';
}
int main() {
ios::sync_with_stdio(0);
cin.tie(NULL);cout.tie(NULL);
int tc = 1; // cin >> tc;
while(tc--) solve();
}